Question

# The magnetic dipole of a bar magnet of geometric length $$18\ cm$$ and pole strength $$100\ Am$$ is:

A
15 Am2
B
18 Am2
C
9 Am2
D
7.5 Am2

Solution

## The correct option is A $$15\ Am^{2}$$Magnetic dipole of a bar magnet$$=m\times 2l$$$$magnetic-length (2l)=\dfrac{5}{6}geometric-length$$$$2l=\dfrac{5}{6} \times 18=15cm=0.15m$$$$=m\times 2l$$$$=100 \times 0.15$$$$=15Am^2$$PhysicsNCERTStandard XII

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