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Question

The magnetic dipole of a bar magnet of geometric length $$18\ cm$$ and pole strength $$100\ Am$$ is:


A
15 Am2
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B
18 Am2
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C
9 Am2
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D
7.5 Am2
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Solution

The correct option is A $$15\ Am^{2}$$
Magnetic dipole of a bar magnet

$$=m\times 2l$$

$$magnetic-length (2l)=\dfrac{5}{6}geometric-length$$

$$2l=\dfrac{5}{6} \times 18=15cm=0.15m$$

$$=m\times 2l$$

$$=100 \times 0.15$$

$$=15Am^2$$


Physics
NCERT
Standard XII

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