The magnetic field at center, $P$ will be

\frac{μ_{0}}{4 π}

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\frac{μ_{0}}{π}

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\frac{μ_{0}}{2 π}

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4 μ_{0} π

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Solution

The correct option is C $\frac{μ_{0}}{2 π}$
$B = \frac{μ_{0}}{4 π} \frac{2 i_{1}}{\frac{r}{2}} - \frac{μ_{0}}{4 π} \frac{2 i_{2}}{\frac{r}{2}} = \frac{μ_{0}}{4 π} \frac{4}{r} (i_{1} - i_{2}) = \frac{μ_{0}}{4 π} \frac{4}{5} (5 - 2.5) = \frac{μ_{0}}{2 π}$

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The magnetic field at center, P will be

The correct option is C μ02πB=μ04π2i1r/2−μ04π2i2r/2=μ04π4r(i1−i2)=μ04π45(5−2.5)=μ02π

The magnetic field at center, $P$ will be

The correct option is C $\frac{μ_{0}}{2 π}$
$B = \frac{μ_{0}}{4 π} \frac{2 i_{1}}{\frac{r}{2}} - \frac{μ_{0}}{4 π} \frac{2 i_{2}}{\frac{r}{2}} = \frac{μ_{0}}{4 π} \frac{4}{r} (i_{1} - i_{2}) = \frac{μ_{0}}{4 π} \frac{4}{5} (5 - 2.5) = \frac{μ_{0}}{2 π}$