The magnetic field at the centre of an equilateral triangular loop of side 2L and carrying a current i is:
A
9μ0i4πL
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3√3μ0i4πL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2√3μ0iπL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3μ0i4πL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A9μ0i4πL a=13×√(2L2−L2) a=L√3 magnetic field due to one side of triangle =μ0i4πL×(cosθ1+cosθ2) =μ0i4π1√3×(2√32) =3μ0i4πL ∵|B| total at centre of triangle = 3×3μ0i4πL =9μ0i4πL