Question

The magnetic field B and the magnetic intensity H in a material are found to be 1.6 T and 1000 A $m^{-1}$ respectively. Calculate the relative permeability ${\mu }_r$ and the susceptibility x of the material.

Answer 1

Here B = 1.6 T, H = 1000 A/m

and $\mu =\frac{B}{H}=\frac{1.6}{1000}$

= $1.6\times {10}^{-3}$

${\mu }_r=\frac{\mu }{{\mu }_0}=\frac{1.6\times {10}^3}{4\pi \times {10}^{-7}}$

= $0.127\times {10}^4$

= $1.3\times {10}^3$

$\mu ={\mu }_0\times$ (1+x)

x = $\frac{\mu }{{\mu }_0^{-1}}={\mu }_r-1$

=$1.3\times {10}^3-1$

= 1300 - 1

= 1299 = $1.299\times {10}^3$

$\approx 1.3\times {10}^3$