The magnetic field component of a wave in free space is given by H-5sin2- 108t- z- A-M the wave is polarised in

The electric field gives the direction of polarisation. E×H= â_̂ẑ nbsp; E×(â_̂ŷ)= â_̂ẑ nbsp; ∴E= â_̂x̂ nbsp; nbsp; nbsp; ...

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Linear Polarization

The magnetic ...

Question

$T h e m a g n e t i c f i e l d c o m p o n e n t o f a w a v e i n f r e e s p a c e i s g i v e n b y \to H = 5 s i n (2 \times 10^{8} t + π z)_{y} A / M$
the wave is polarised in

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_{i} = 24 c o s (3 \times 10^{8} t - β y)_{z}

μ = μ_{0}

ϵ = 9 ϵ_{0}

y \geq 0

\to E = 5 cos (ω t + β z) {^a}_{x} - 5 sin (ω t + β z + 180^{\circ}) {^a}_{y} A / m

¯ ¯¯ ¯ E = 5 cos (π \times 10^{8} t - π z) {^a}_{x} V / m

\to H

\to H =^x \frac{5 \sqrt{3}}{η_{0}} c o s (ω t - β z) +^y \frac{5}{η_{0}} s i n (ω t - β z + \frac{π}{2})

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