The magnetic field due to a current carrying loop of radius 12 cm at its centre is 0-5 - 10-4 T- Find the magnetic field due to the loop at an axial point 5 cm away from the centre-

Magnetic field at centre #160; B_o = 0.5× 10^ 4 T #160; #160; #160; #160; #160; #160;Radius #160; #160; R = 12 cm = 0.12 m Di ...

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Standard XII

Physics

Magnetic Field

The magnetic ...

Question

The magnetic field due to a current carrying loop of radius 12 cm at its centre is $0.5 \times 10^{- 4}$ T. Find the magnetic field due to the loop at an axial point 5 cm away from the centre.

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Solution

Magnetic field at centre $B_{o} = 0.5 \times 10^{- 4} T$
Radius $R = 12 c m = 0.12 m$
Distance of axial point $l = 5 c m = .05 m$

Magnetic field at an axial point $B_{x} = \frac{B_{o} R^{3}}{(R^{2} + x^{2})^{3 / 2}}$

$B_{x = .05} = \frac{0.5 \times 10^{- 4} (0.12)^{3}}{((0.12)^{2} + (0.05)^{2})^{3 / 2}} = 0.4 \times 10^{- 4} T$

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The magnetic field due to a current carrying loop of radius 12 cm at its centre is 0.5×10−4 T. Find the magnetic field due to the loop at an axial point 5 cm away from the centre.

Magnetic field at centre Bo=0.5×10−4 T Radius R=12 cm=0.12 mDistance of axial point l=5cm=.05mMagnetic field at an axial point Bx=BoR3(R2+x2)3/2Bx=.05=0.5×10−4(0.12)3((0.12)2+(0.05)2)3/2=0.4×10−4 T

The magnetic field due to a current carrying loop of radius 12 cm at its centre is $0.5 \times 10^{- 4}$ T. Find the magnetic field due to the loop at an axial point 5 cm away from the centre.