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Question

The magnetic field due to a current in a straight line wire segment of length L at a point on its perpendicular bisector at a distance r: (r>>L)

A
Decrease as 1r
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B
Decreases as 1r2
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C
Decreases as 1r3
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D
Approaches a finite limit as r
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Solution

The correct option is B Decreases as 1r2
Magnetic field due to a finite current carrying wire is given by:
B=μoI4πr(sinθ1+sinθ2)
=μoI4πr(2×L/2(L/2)2+r2)
Using r>>L,
BμoI4πr2

Hence, option B is correct

676288_635163_ans_04d0b0ca71e646ba9bfabc60f9f5c0f3.png

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