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Question

The magnetic field due to a square loop of side a carrying a current I at its centre is

A
μ0i2a
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B
μ0i2πa
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C
μ0i2πa
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D
2μ0iπa
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Solution

The correct option is D 2μ0iπa
B=[mu0i4πa(cos45ocos135o)]×4

=μ0iπa22

=2μ0iπa

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