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Question

The magnetic field due to the earth has a horizontal component of 26 μT at a place where the dip is 60°. Find the vertical component and the magnitude of the field.

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Solution

Given:
Horizontal component of Earth's magnetic field, B = 26 μT ​
Angle of dip, δ = 60°
The horizontal component of Earth's magnetic field BH is given by
BH = Bcosδ
Here,
B = Total magnetic field of Earth
On substituting the respective values, we get
26×10-6=B×12B=52×10-6=52 μT
The vertical component of Earth's magnetic field By is given by
By=BsinδBy=52×10-6×32By=44.98 μT=45 μT

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