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Physics

Faraday's Law

The magnetic ...

Question

The magnetic field in a coil of $100$ turns and $40$ square cm area is increased from $1$ Tesla to $6$ Tesla in $2$ second. The magnetic field is perpendicular to the coil. The e.m.f. generated in it is

10^{4} V

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1.2 V

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1.0 V

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10^{- 2} V

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Solution

The correct option is D $1.0 V$
$e = - N (\frac{Δ B}{Δ t}) . A c o s θ = - 100 \times \frac{(6 - 1)}{2} \times (40 \times 10^{- 4}) c o s 0$

$\Rightarrow | e | = 1 V$

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The magnetic field in a coil of 100 turns and 40 square cm area is increased from 1 Tesla to 6 Tesla in 2 second. The magnetic field is perpendicular to the coil. The e.m.f. generated in it is

The correct option is D 1.0Ve=−N(ΔBΔt).Acosθ=−100×(6−1)2×(40×10−4)cos0⇒|e|=1V

The magnetic field in a coil of $100$ turns and $40$ square cm area is increased from $1$ Tesla to $6$ Tesla in $2$ second. The magnetic field is perpendicular to the coil. The e.m.f. generated in it is

The correct option is D $1.0 V$
$e = - N (\frac{Δ B}{Δ t}) . A c o s θ = - 100 \times \frac{(6 - 1)}{2} \times (40 \times 10^{- 4}) c o s 0$

$\Rightarrow | e | = 1 V$