Question

The magnetic field of a plane electromagnetic wave is given by: →B=B0^i[cos(kz−ωt)]+B1^jcos(kz+ωt), Where B0=3×10−5 T and B1=2×10−6 T The rms value of the force experienced by a stationary charge Q=10−4 C at z=0 is closest to

A
0.1 N
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B
0.6 N
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C
3×102 N
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D
0.9 N
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Solution

The correct option is B 0.6 NGiven: B0=3×10−5 T ,B1=2×10−6 T Q=10−4 C at z=0 Net magnetic field B0=√B20+B21=√302+22×10−6≈30×10−6 T So, Electric field E0=cB=3×108×30×10−6=9×103 V/m Now, rms value of the electric field Erms=E0√2=9√2×103 V/m Force on the charge, F=ErmsQ F=9√2×103×10−4=0.64 N F≃0.6 N Hence option (A) is correct.

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