Question

The magnetic field through a single loop of wire,12 cm in radius and $8.5\Omega$ resistance, changes with time as shown in the figure. The magnetic field is perpendicular to the plane of the loop plot induced current as a function of time.

Answer 1

We know,
$\epsilon =\frac{-d\phi }{dt}=\frac{-d\left(BA\right)}{dt}=A\frac{dB}{dt}$
$I=\frac{\epsilon }{R}=\frac{-A\left(\frac{dB}{dt}\right)}{R}$
For $0<t<2$
$=\frac{-3.14(0.12{)}^2?1}{2?8.5}=0.0026A$
For $0<t<2$
$=\frac{-3.14(0.12{)}^2?1}{2?8.5}=0.0026A$
For, $2<t<4$
$\frac{dB}{dt}=0\Rightarrow I=0$
For, $4<t<6$