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Question

The magnetic flux linked with a coil at any instant t is given by ϕ=5t3100t+300, the emf induced in coil at t=2s is

A
40V
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B
40V
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C
140V
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D
300V
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Solution

The correct option is A 40V
Given , ϕ=5t3100t+300,t=2s
Now , dϕdt=15t2100
The induced emf in a coil is given by ,
e=dϕdt
Hence , e=(15t2100)=15t2+100
at t=2s
e=15×22+100=60+100=40V


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