The magnetic flux near the axis and inside the air core solenoid of length 60 cm carrying current ′I′ is 1.57×10−6Wb. Its magnetic moment will be (cross - sectional area of a solenoid is very small as compared to its length, μ0=4π×10−7SIunit)
A
0.25A
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B
0.50A
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C
0.75A
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D
1A
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Solution
The correct option is C0.75A
Magnetic induction inside the solenoid
B=μ0NIL
Magnetic Flux , ϕ=BA=μ0NIAL
Magnetic moment = NIA=ϕLμ0=1.57×10−6×0.64×3.141×10−7=0.75Am2