The magnetic flux through a loop of resistance 10- is given by -5t2-4t-1 Wb- How much current is induced in the loop after 0-2 s-

The magnetic flux $ϕ$ (in weber) linked with a coil of resistance 10 $Ω$ varies with time t (in second) as $ϕ$ =8 $t^{2}$ -4t+1.The current induced in the coil at is t=0.1 sec is

Q. The instantaneous magnetic flux associated with a closed loop of resistance

10 Ω

is given by,

ϕ = 6 t^{2} - 5 t + 1

, then the magnitude of induced current at

t = 0.25 s

will be -

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The magnetic flux through a loop of resistance 10Ω is given by (ϕ=5t2−4t+1Wb). How much current is induced in the loop after 0.2 s?

The correct option is B 0.2 AThe flux is given by ϕ=5t2−4t+1. The emf induced in the resistance would be equal toe=−dϕdt=10t−4.Thus, the current induced in the loop is equal toi=eR=−(10t−410)at t=0.2s, we havei=−(0×0.2−410)=210=0.2 A

The magnetic flux through a loop of resistance $10 Ω$ is given by $(ϕ = 5 t^{2} - 4 t + 1 W b)$ . How much current is induced in the loop after $0.2$ s?