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Question

The magnetic force acting on a charged particle of charge2μC in a magnetic field of 2T acting in y-direction, when the particle velocity is (2ˇi+3ˇj) ×106ms1 is :

A
8 N in Z-direction
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B
4 N in Z-direction
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C
8 N in y-direction
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D
4 N in Y-direction
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Solution

The correct option is A 8 N in Z-direction
Force on a moving charge in magnetic field =q(v×B)
F=2×106(2^i+3^j)×2^j×106
F=2×106(2^i×2^j)×106
F=8^kN
Therefore, A is correct option.

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