The magnetic force experienced by an electron moving with a velocity of 2775kms−1 at an angle of 30∘ to a magentic field is 7.336×10−14N. What is the strength of the magnetic field (in Tesla)? Given, the electron charge, e=1.6×10−19C
A
1.28
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B
0.33
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C
0.26
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D
1.09
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Solution
The correct option is B0.33 Magnetic force (F) experienced by the electron in the magnetic field B is given by: F=Bev(sinθ) where velocity of the electron, v = 2775kms−1 = 27.75×105ms−1 and angle between velocity of the electron and magnetic field, θ=30∘ Substituting the given values, we get 7.336×10−14 = B×1.6×10−19×27.75×105×sin(30∘) On solving, B=0.33T.