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Question

The magnetic force experienced by an electron moving with a velocity of 2775 km s1 at an angle of 30 to a magentic field is 7.336×1014 N. What is the strength of the magnetic field (in Tesla)? Given, the electron charge, e=1.6×1019 C

A
1.28
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B
0.33
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C
0.26
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D
1.09
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Solution

The correct option is B 0.33
Magnetic force (F) experienced by the electron in the magnetic field B is given by:
F=Bev(sinθ)
where velocity of the electron, v = 2775 km s1 = 27.75×105 m s1 and angle between velocity of the electron and magnetic field, θ=30
Substituting the given values, we get
7.336×1014 = B×1.6×1019 ×27.75×105×sin(30)
On solving, B=0.33 T.

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