Question

The magnetic force on a current carrying wire placed in uniform magnetic field if the wire is oriented perpendicular to magnetic field, is

• A. $0$
• B. $ILB$
• C. $2ILB$
• D. $ILB/2$

Answer 1

The correct option is B $ILB$

Let current flowing = I

Length of the wire = L and

Magnetic field = B

Using,

$F=ILB\sin \theta$

Here $\theta =90°$

$⟹F=ILB$