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Question

The magnetic induction at a distance 'a' from a long straight wire carrying a current. I has magnitude

A
μ04π×Ia2
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B
μ04π×Ia
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C
μ04π×2Ia
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D
μ04π×I2a
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Solution

The correct option is C μ04π×2Ia
Given: Distance from the wire is "a" carrying current "I"

Solution:

Formula for magnetic induction for a long wire carrying current I at distance r is μI2πr
So by substituting values in the formula we getμI2πa
By multiplying both numerator and denominator by 2 we get 2μI4πa

The correct opt : C

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