The magnetic induction at a point $0.1 m$ away from a long wire which carries a current of $10 A (μ_{0} = 4 π \times 10^{- 7} S . I . U n i t)$ is

2 \times 10^{- 5} T

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4 \times 10^{- 5} T

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10^{- 5} T

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6 \times 10^{- 5} T

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Solution

The correct option is B $2 \times 10^{- 5} T$
$B = \frac{μ_{0} i}{2 π r}$
$= \frac{2 \times 10^{- 7} \times 10}{0 \cdot 1}$
$= 2 \times 10^{- 5} T$

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The magnetic induction at a point 0.1 m away from a long wire which carries a current of 10A(μ0=4π×10−7S.I.Unit) is

The correct option is B 2×10−5TB=μ0i2πr =2×10−7×100⋅1 =2×10−5T

The magnetic induction at a point $0.1 m$ away from a long wire which carries a current of $10 A (μ_{0} = 4 π \times 10^{- 7} S . I . U n i t)$ is

The correct option is B $2 \times 10^{- 5} T$
$B = \frac{μ_{0} i}{2 π r}$
$= \frac{2 \times 10^{- 7} \times 10}{0 \cdot 1}$
$= 2 \times 10^{- 5} T$