The magnetic induction at a point P which is distant 4 cm from a long current carrying wire is 10−3 Telsa.The field of induction at a distance 12 cm from the same current would be
A
3.33×10−9 Tesla
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B
1.11×10−4 Tesla
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C
3×10−3 Tesla
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D
9×10−2 Tesla
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Solution
The correct option is A
3.33×10−9 Tesla
B=μ04π.2ir⇒B1B2=r2r1⇒10−3B2=124⇒B2=3.33×10−9 Tesla