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Standard XII

Physics

Magnetic Moment

The magnetic ...

Question

The magnetic induction field strength at a distance 0.2 m on the axial line of a short bar magnet of moment 3.6 Am $^{2}$ is

4.5 \times 10^{- 4} T

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9 \times 10^{- 4} T

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9 \times 10^{- 5} T

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4.5 \times 10^{- 5} T

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Solution

The correct option is D $9 \times 10^{- 5} T$
$d = 0.2 m$
$m = 3.6$
$B a r t a l = \frac{z μ_{0} m}{4 π d^{3}}$
$= \frac{2 \times 4 π \times 10^{- 7} \times 3.6}{4 π \times (0.2)^{3}}$
$= 9 \times 10^{- 5}$

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The magnetic induction field strength at a distance 0.2 m on the axial line of a short bar magnet of moment 3.6 Am2is

The correct option is D 9×10−5Td=0.2mm=3.6Bartal=zμ0m4πd3=2×4π×10−7×3.64π×(0.2)3=9×10−5

The magnetic induction field strength at a distance 0.2 m on the axial line of a short bar magnet of moment 3.6 Am $^{2}$ is

The correct option is D $9 \times 10^{- 5} T$
$d = 0.2 m$
$m = 3.6$
$B a r t a l = \frac{z μ_{0} m}{4 π d^{3}}$
$= \frac{2 \times 4 π \times 10^{- 7} \times 3.6}{4 π \times (0.2)^{3}}$
$= 9 \times 10^{- 5}$