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Question

The magnetic moment (B.M) of [Fe(CN)6]4 & [Fe(H2O)6]2+ respectively are:

A
24,zero
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B
24,24
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C
zero,24
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D
zero,zero
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Solution

The correct option is D zero,24
[Fe[CN]6]4Fe2+3d6
Lowspin complex 0 unpaired e
μ=n(n+2)0(0+2)=0
[Fe(H2O)6]2+4 unpaired e4(4+2)=24

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