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Standard XII
Chemistry
Isomerism in Coordination Compounds
The magnetic ...
Question
The magnetic moment
μ
, of transition metals is related to the number of unpaired electrons, n as:
A
μ
=
n
(
n
+
2
)
2
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B
μ
=
n
2
(
n
+
2
)
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C
μ
=
n
(
n
+
2
)
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D
μ
=
√
n
(
n
+
2
)
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Solution
The correct option is
A
μ
=
√
n
(
n
+
2
)
Magnetic moment is
μ
=
√
n
(
n
+
2
)
where n is no of unpaired electron.
Suggest Corrections
0
Similar questions
Q.
Assertion :The magnetic moment (
μ
) of an electron revolving around the nucleus decreases with increasing principle quantum number (
n
). Reason: Magnetic moment of the revolving electron
μ
∝
n
Q.
The substances which contain species with unpaired electrons in
their orbitals behave as paramagnetic substances. Such substances
are weakly attracted by the magnetic field. The paramagnetism is
expressed in terms of magnetic moment. The magnetic moment is
related to the number of unpaired electrons according to the
following relation:
Magnetic moment,
μ
=
√
n
(
n
+
2
)
B
M
where,
n
=
number of unpaired electrons.
B
M
stands for Bohr magneton, a unit of magnetic moment.
1
B
M
=
e
h
4
π
m
c
=
9.27
×
10
−
24
A
m
2
or
J
T
−
1
Which of the following ions are diamagnetic?
Q.
The magnetic moment
(
μ
)
of a revolvng electron around the nucleus varies with principle quantum number n as
Q.
The magnetic moment
(
μ
)
of a revolving electron around the nucleus varies with principal quantum number
n
as :
Q.
The magnetic moment
(
μ
)
of an electron revolving around the nucleus, varies with principal quantum number
n
as,
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