Question

The magnetic moment of a divalent ion in aqueous solution with atomic number 25 is:

• A. 5.47 B.M
• B. 2.9 B.M
• C. 6.9 B.M
• D. 6.7 B.M

Answer 1

Answer: (A)

5.47 B.M

electronic configuration of the element with atomic number 25(divalent ion) will be $\left[Ar\right]3d^5$,having $5$ unpaired electrons.

magnetic moment will be $\sqrt{n(n+2)}$

where n is unpaired electrons

n=5

$\sqrt{5(5+2)}=\sqrt{35}=5.47$