The magnetic moment of a magnet of mass $75$ $g$ is $9 \times 10^{- 7} A m^{2}$ . If the density of the material of magnet is $7.5 \times 10^{3}$ then intensity of magnetisation will be

90 A m^{- 1}

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0.09 A m^{- 1}

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0.9 A m^{- 1}

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9 A m^{- 1}

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Solution

The correct option is B $0.09 A m^{- 1}$
$I = \frac{M}{V} = \frac{M}{m / ρ} = \frac{M ρ}{m}$ $= \frac{9 \times 10^{- 7} \times 4.5 \times 10^{3}}{75 \times 10^{- 3}} = 0.09 A m^{- 1}$

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