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Crystal Field Split in Octahedral Complexes

The magnetic ...

Question

The magnetic moment of an octahedral homoleptic $M n (I I)$ complex is $5.9 B M$ . The suitable ligand for this complex is:

A

C N^{-}

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B

N C S^{-}

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C

C O

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D

E t h y l e n e d i a m i n e

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Solution

The correct option is B $N C S^{-}$
$μ = 5.9$ BM
$∴$ n(no. of unpaired e) $= 5$

Cation $M n^{I I} - 3 d^{5}$ configuration only possible for relatively weak ligand.

$∴ N C S^{-}$

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