The magnetic moment of bar magnet of length 12 cm of magnetic pole strength of 200 mA-m is 0.024A-m $^{2}$ .

True

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False

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Solution

The correct option is A True
$q m$ , magnetic pole strength = 200mA-m
$\Rightarrow 200 \times 10^{- 3} A - m$
$2 \to l$ ; length of magnet directed from S-pole to N-pole = 12cm
$\Rightarrow$ 0.12m
Magnetic dipolemoment; $\to m = q m \times 2 \to l$
$\Rightarrow 200 \times 10^{- 3} \times 0.12 A - m^{2}$
$\Rightarrow 0.2 \times 0.12 A m^{2}$
$\Rightarrow 0.024 A m^{2} .$
Hence, Option : A (true).

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The magnetic moment of bar magnet of length 12 cm of magnetic pole strength of 200 mA-m is 0.024A-m2.

The correct option is A Trueqm, magnetic pole strength = 200mA-m ⇒200×10−3A−m2→l; length of magnet directed from S-pole to N-pole = 12cm⇒ 0.12mMagnetic dipolemoment; →m=qm×2→l⇒200×10−3×0.12A−m2⇒0.2×0.12Am2⇒0.024Am2.Hence, Option : A (true).

The magnetic moment of bar magnet of length 12 cm of magnetic pole strength of 200 mA-m is 0.024A-m $^{2}$ .