Question

The magnetic moment of $C{e}^{3+}$ ion on the basis of spin only formula will be _____ B.M.

• A. 1.232
• B. 1.332
• C. 1.532
• D. 1.732

Answer 1

The correct option is D 1.732

$C{e}^{3+}:\left[Xe\right]6s^1$

Number of unpaired $e^{-}=1=n$

So, $\mu =\sqrt{n(n+2)}$

$\therefore \mu =\sqrt{1(1+2)}=\sqrt{3}=1.732BM$