Question

The magnetic moment of $[Ni{X}_4{]}^{2-}$ ion is found to be zero. Then the ion is : $(X=$ monodentate anionic ligand).

• A. $s{p}^3$ hybridised
• B. $sp{d}^2$ hybridised
• C. $ds{p}^2$ hybridised
• D. $d^{2}sp$ hybirdised

Answer 1

The correct option is C $ds{p}^2$ hybridised

Zero magnetic moment of $[Ni{X}_4{]}^{2-}$ indicates that all electrons are paired.
This is possible when $N{i}^{2+}$ ion with $3d^8$ outer electronic configuration undergoes $ds{p}^2$ hybridization to form inner orbital or low spin or spin paired complex.