The magnetic moments of Cr (Z=24), Mn (Z=25) and Fe (Z=26) are x,y and z respectively. Hence,
A
x=y=z
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B
x=z<y
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C
x<y<z
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D
x>y>z
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Solution
The correct option is Dx>y>z Electronic configuration of Fe(26)=1s22s22p63s23p63d64s2
So, the number of unpaired electrons n=4
Electronic configuration of Cr(24)=1s22s22p63s23p63d54s1
So, the number of unpaired electrons, n=6
Electronic configuration of Mn(25)=1s22s22p63s23p63d54s2
So, the number of unpaired electrons, n=5
Magnetic moment(μ)=√n(n+2)B.M.
Where, n= number of unpaired electrons.
Greater the number of unpaired electrons, greater will be the magnetic moment.
Thus, the correct order is x>y>z.