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Question

The magnetic moments of Cr (Z=24), Mn (Z=25) and Fe (Z=26) are x, y and z respectively. Hence,

A
x=y=z
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B
x=z<y
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C
x<y<z
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D
x>y>z
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Solution

The correct option is D x>y>z
Electronic configuration of
Fe(26)=1s22s22p63s23p63d64s2

So, the number of unpaired electrons n=4

Electronic configuration of
Cr(24)=1s22s22p63s23p63d54s1

So, the number of unpaired electrons, n=6

Electronic configuration of
Mn(25)=1s22s22p63s23p63d54s2

So, the number of unpaired electrons, n=5

Magnetic moment (μ)=n(n+2) B.M.
Where, n= number of unpaired electrons.
Greater the number of unpaired electrons, greater will be the magnetic moment.
Thus, the correct order is x>y>z.

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