Question

The magnetic needle of a tangent galvanometer is deflected at an angle $30$ due to a magnet. The horizontal component of the earth's magnetic field$0.34\times {10}^{-4}T$ is along the plane of the coil. The magnetic intensity is:

Answer 1

Step 1: Given data,

Angle of deflection $={30}^{\circ }$

The horizontal component of the magnetic field $B_H=0.34\times {10}^{-4}T$

Step 2: Solve for the magnetic intensity.

The magnetic intensity is $B_H\tan \left(\theta \right)$

$$\begin{gathered} =0.34\times {10}^{-4}\times \tan \left({30}^{\circ }\right) \\ =0.34\times {10}^{-4}\times 0.577 \\ =1.96\times {10}^{-5}T \end{gathered}$$

Thus, the magnetic intensity is $1.96\times {10}^{-5}T$