Question

The magnetic susceptibility of a paramagnetic substance is $3\times {10}^{-4}A{m}^{-1}$. The intensity of magnetisation will be : ( $H=4\times {10}^3$ )

• A. $24A{m}^{-1}$
• B. $3\times {10}^{8}A{m}^{-1}$
• C. $12\times {10}^{8}A{m}^{-1}$
• D. $1.2A{m}^{-1}$

Answer 1

Answer: (D)

$1.2A{m}^{-1}$

Relation between magnetizing field and intensity of magnetization is,
$\chi =\frac{I}{H}=0$ or $I=\chi \times H=3\times {10}^{-4}\times 4\times {10}^3$
$=1.2A{m}^{-1}$