The magnetic susceptibility of a rod is 499. The absolute permeability of vacuum is μ0=4π×10−7Hm−1. The absolute permeability of the material of the rod is-
A
4π×10−4Hm−1
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B
3π×10−4Hm−1
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C
2π×10−4Hm−1
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D
π×10−4Hm−1
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Solution
The correct option is C2π×10−4Hm−1 Given, χ=499;μ0=4π×10−7
The absolute permeability of the material of the rod is,
μ=μ0(1+χ)
=4π×10−7(500)
=2π×10−4Hm−1
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Hence, (C) is the correct answer.