The magnification for a mirror is $- 3$ . How are $u$ and $v$ related?

Open in App

Solution

We know that ,
$m = - \frac{v}{u}$
Given : $m = - 3$
$∴ - \frac{v}{u} = - 3$
$v = 3 u$
Since $^{'} u^{'}$ is always negative
$v = - 3 u$
The above equation shows how $u$ and $v$ related.

Suggest Corrections

Similar questions

Relate the image distance ( $v$ ), object distance ( $u$ ) , image height ( $h^{^{'}}$ ) and object height ( $h$ ) to the formula of magnification $(M)$ for a mirror.

why is magnification in terms of mirrors -v/u whereas in lenses it is v/u ?

The erect image formed by a concave mirror is of size double the size of object. How are u and v related ?

The image formed by a convex mirror is of size one-third the size of object. How are u and v related ?

Q. The relation among

u

v

and

f

for a mirror is:

Join BYJU'S Learning Program

The magnification for a mirror is −3. How are u and v related?

We know that , m=−vu Given : m=−3 ∴−vu=−3 v=3u Since ′u′ is always negative v=−3u The above equation shows how u and v related.

The magnification for a mirror is $- 3$ . How are $u$ and $v$ related?

We know that ,
$m = - \frac{v}{u}$
Given : $m = - 3$
$∴ - \frac{v}{u} = - 3$
$v = 3 u$
Since $^{'} u^{'}$ is always negative
$v = - 3 u$
The above equation shows how $u$ and $v$ related.