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Cutting of Thin Lenses

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Question

The magnifying power of a telescope is 9. When it is adjusted for parallel rays. The distance between the objective and eyepiece is 20 cm. The focal length of its lenses are.

A

10 cm, 10 cm

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B

15 cm, 5 cm

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C

18 cm, 2 cm

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D

11 cm, 9 cm

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Solution

The correct option is C
18 cm, 2 cm

$m = \frac{f_{0}}{f_{e}} = 9$

$f_{0} = 9 f_{e}$ ... (i)

$f_{0} + f_{e} = 20$ ... (ii)

By solving equation (i) and (ii)

$f_{e}$ = 2 cm, $f_{0}$ = 18 cm

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