Question

The magnifying power of an astronomical telescope is $8$, then the ratio of the focal length of the objective to the focal length of the eye piece is:

• A. $8$
• B. $\frac{1}{8}$
• C. $0.45$
• D. None of these

Answer 1

The correct option is A $8$

The magnification of a telescope changes as the eyepiece is changed. Magnification can be calculated by dividing the focal length of objective by the focal length of the eyepiece. In this case it is given as 8.