The magnifying power of the objective and eye-piece of a compound microscope are $m_{1}$ and $m_{2}$ . The magnifying power of microscope will be __________.

m_{1}

+

m_{2}

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m_{1}

m_{2}

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m_{1}

m_{2}

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m_{1}

m_{2}

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Solution

The correct option is B $m_{1}$ . $m_{2}$
In compound microscope, total magnifying power of microscope is given by the multiplication of the magnifying power of the objective lens and eye-piece.
Thus magnifying power of microscope $m = m_{1} \times m_{2}$

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The magnifying power of the objective and eye-piece of a compound microscope are m1 and m2 . The magnifying power of microscope will be __________.

The correct option is B m1 . m2In compound microscope, total magnifying power of microscope is given by the multiplication of the magnifying power of the objective lens and eye-piece. Thus magnifying power of microscope m=m1×m2

The magnifying power of the objective and eye-piece of a compound microscope are $m_{1}$ and $m_{2}$ . The magnifying power of microscope will be __________.

The correct option is B $m_{1}$ . $m_{2}$
In compound microscope, total magnifying power of microscope is given by the multiplication of the magnifying power of the objective lens and eye-piece.
Thus magnifying power of microscope $m = m_{1} \times m_{2}$