Question

The magnifying power of the objective of a compound microscope is $7.$ If the magnifying power of the microscope is $35$, then the magnifying power of eyepiece will be :

• A. $245$
• B. $5$
• C. $28$
• D. $42$

Answer 1

The correct option is B $5$

Given,

Magnifying power of objective,. $m_o=7$

Magnifying power of microscope = $35$

Magnifying power $=m_0\times m_e$

$35=7\times m_e$

$m_e=5$