The magnitude of a vector which results on addition of two vectors $6^i + 7^j$ and $3^i + 4^j$ :

\sqrt{136}

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\sqrt{132}

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\sqrt{202}

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\sqrt{160}

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Solution

The correct option is C $\sqrt{202}$
Let $\to R = (6^i + 7^j) + (3^i + 4^j) = (9^i + 11^j)$
$∣ ∣ \to R ∣ ∣ = \sqrt{9^{2} + 11^{2}} = \sqrt{81 + 121} = \sqrt{202}$

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