Question

The magnitude of an orbital angular momentum vector of an electron is $\sqrt{6}$$\frac{h}{2\pi }$. Into how many components will the vector split if an external field is applied to it?

• A. 3
• B. 5
• C. 7
• D. 10

Answer 1

The correct option is B 5

The orbital angular momentum is given by $\sqrt{l(l+1)}\times h/2\pi$
In the question it is given to be $\sqrt{6}\times h/2\pi$
so, it means $\sqrt{l(l+1)}$ = $\sqrt{6}$
l = 2
The possible values of magnetic quantum number for l=2 will be
$m_l$ =$-2,-1,0,1,2$
So, the vector can split into five components in the presence of external magnetic field.