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Question

The magnitude of difference in oxidation number of O in OF2 and ​ O2F2 respectively is

A
1
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B
1.0
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C
1.00
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Solution

OF2:
Let y be the oxidation state of "O" in OF2​.
Since the overall charge of a neutral molecule is zero. The sum of oxidation states of all elements in it should be equal to 0.
Therefore, y+2(1)=0y=+2

Hence, the oxidation state of "O "in OF2​ is +2.

O2F2 :
Since fluorine is more electronegative than oxygen so, oxidation state of fluorine is 1 in all its compounds. Let oxidation number of O atom in O2F2 is x.
2×x+1×(1)=0x=+1

1F+1O+1O1F
So, oxidation number of oxygen will be +1 on O2F2
Difference : (+2)(+1)=1

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