Question

The magnitude of electric field intensity E, such electron, placed in the field, would experience an electric force equal to its weight is :

• A. $5.6\times {10}^{-7}N{C}^{-1}$
• B. $5.6\times {10}^{-8}N{C}^{-1}$
• C. $5.6\times {10}^{-10}N{C}^{-1}$
• D. $5.6\times {10}^{-11}N{C}^{-1}$

Answer 1

The correct option is D $5.6\times {10}^{-11}N{C}^{-1}$

Strength of elelctric field is given as:

$E=\frac{F}{q_o}$

Here, $q_o=e;F=mg$

$eE=mg$

$E=\frac{mg}{e}$

$E=\frac{9.109\times {10}^{-31}\times 10}{1.6\times {10}^{-19}}$

$E=5.69\times {10}^{-11}N{C}^{-1}$