The magnitude of force exerted by the brakes on the wheel of a motorcar, which is moving with a velocity of $72 km/h$ and takes $5 s$ to stop after the application of brakes, is -

Mass of the motorcar along with the passengers is $800 kg$ .

1600 N

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3200 N

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2400 N

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4800 N

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Solution

The correct option is B $3200 N$
From, $v = u + a t$ ,

$a = \frac{v - u}{t} = \frac{0 - 72 \times \frac{5}{18}}{5} = - 4 {m/s}^{2}$

So, magnitude of force applied by the brakes on the wheel of a motorcar,

$F = m a = 800 \times 4 = 3200 N$

Hence, option $(B)$ is the correct answer.

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The magnitude of force exerted by the brakes on the wheel of a motorcar, which is moving with a velocity of 72 km/h and takes 5 s to stop after the application of brakes, is - Mass of the motorcar along with the passengers is 800 kg.

The correct option is B 3200 NFrom, v=u+at, a=v−ut=0−72×5185=−4 m/s2 So, magnitude of force applied by the brakes on the wheel of a motorcar, F=ma=800×4=3200 N Hence, option (B) is the correct answer.

The magnitude of force exerted by the brakes on the wheel of a motorcar, which is moving with a velocity of $72 km/h$ and takes $5 s$ to stop after the application of brakes, is -

Mass of the motorcar along with the passengers is $800 kg$ .

The correct option is B $3200 N$
From, $v = u + a t$ ,

$a = \frac{v - u}{t} = \frac{0 - 72 \times \frac{5}{18}}{5} = - 4 {m/s}^{2}$

So, magnitude of force applied by the brakes on the wheel of a motorcar,

$F = m a = 800 \times 4 = 3200 N$

Hence, option $(B)$ is the correct answer.