The magnitude of frequency response of an underdamped second order system is 5 at 0rad/sec and peaks to 10√3 at 5√2rad/sec. The transfer function of the system is
A
500s2+10s+100
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B
375s2+5s+75
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C
720s2+12s+144
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D
1125s2+25s+225
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Solution
The correct option is A500s2+10s+100 Mr=52ξ√1−ξ2=10√3 orξ=12
Also, ωr=ωn√1−2Z2 5√2=ωn√1−2×(14) orωn=10rad/sec
Only option (a) satisfies the conditions