The magnitude of gravitational potential energy of the earth-satellite system is U with zero potential energy at infinite separation.The kinetic energy of satellite is K. Mass of satellite << Mass of earth. Then

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Solution

The correct option is B

Kinetic energy of satellite is K = $\frac{G M m}{2 r}$

While magnitude of potential energy

$U = \frac{G M m}{r}$ $∴ K = \frac{U}{2}$

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The magnitude of gravitational potential energy of the earth-satellite system is U with zero potential energy at infinite separation.The kinetic energy of satellite is K. Mass of satellite << Mass of earth. Then

The correct option is B Kinetic energy of satellite is K = GMm2r While magnitude of potential energy U=GMmr ∴K=U2

The correct option is B

Kinetic energy of satellite is K = $\frac{G M m}{2 r}$

While magnitude of potential energy

$U = \frac{G M m}{r}$ $∴ K = \frac{U}{2}$