The magnitude of 'I' in ampere unit is
Applying Kirchoff's law in the following figure.
At junction A:
I+I1+I2=1 ....(i)
For loop (i)
−60I+(15+5)I1 = 0
⇒ I1=3I ....(ii)
For loop (2)
−(15+5)I1+10 I2=0
2I1=I2 .....(iii)
On solving equation (i),(ii) and (iii) we get I=0.1 A
Short Trick: Branch current = main current (Resistance of opposite branchTotal resistance)
⇒ I=1×[203203+60]
=0.1 A