Question

The magnitude of linear momentum of a particle moving at a relativistic speed v is proportional to

(a) v

(b) 1 − v²/c²

(c) $\sqrt{1-v^2/c^2}$

(d) none of these

Answer 1

(d) none of these

Linear momentum of a particle moving at a relativistic speed v is given by
$p=\frac{m_{o}v}{\sqrt{1-{\displaystyle \frac{v^2}{c^2}}}}$

Here, m_​o is the rest mass of the particle.

So, linear momentum is proportional to $\frac{v}{\sqrt{1-{\displaystyle \frac{v^2}{c^2}}}}$.

Hence, none of the above options is correct.