Question

The magnitude of magnetic moment of the current loop shown in the figure is

• A. $I{a}^2$
• B. $\sqrt{2}I{a}^2$
• C. $Zero$
• D. $\frac{\sqrt{3}}{2}I{a}^2$

Answer 1

The correct option is B $\sqrt{2}I{a}^2$

The loop can be divided into two square loops.
The magnetic moments of loops are perpendicular to each other.
For each square loop, $M=I{a}^2,$
We have $M_1=M_2=I{a}^2$
The net magnetic moment is
$M=\sqrt{M_1^2+M_2^2}$
$=\sqrt{2}{M}_1=\sqrt{2}I{a}^2$