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Question

The magnitude of spin angular momentum of an electron is given by:

A
S=s(s+1)h2π
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B
S=sh2π
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C
S=32×h2π
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D
S=±12×h2π
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Solution

The correct options are
A S=s(s+1)h2π
D S=32×h2π
The magnitude of spin angular momentum of an electron is given by s(s+1)h2π
For a single electron s=±12 but for calculating spin angular momentum of an electron on positive value of s is taken.
12(12+1)h2π
=32×(h2π)


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