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Byju's Answer
Standard XII
Chemistry
Quantum Numbers
The magnitude...
Question
The magnitude of spin angular momentum of an electron is given by:
A
S
=
√
s
(
s
+
1
)
h
2
π
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B
S
=
s
h
2
π
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C
S
=
√
3
2
×
h
2
π
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D
S
=
±
1
2
×
h
2
π
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Solution
The correct options are
A
S
=
√
s
(
s
+
1
)
h
2
π
D
S
=
√
3
2
×
h
2
π
The magnitude of spin angular momentum of an electron is given by
√
s
(
s
+
1
)
h
2
π
For a single electron
s
=
±
1
2
but for calculating spin angular momentum of an electron on positive value of s is taken.
√
1
2
(
1
2
+
1
)
h
2
π
=
√
3
2
×
(
h
2
π
)
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